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113121112431329 is a prime number
BaseRepresentation
bin11001101110001000001111…
…101110010001101011100001
3112211112021100211020000221222
4121232020033232101223201
5104311334014240300304
61040331042135024425
732553505422456242
oct3156101756215341
9484467324200858
10113121112431329
11330534379a7122
121082b76780b115
134b173765cc7c2
141dd113bbd6cc9
15d128168eb4be
hex66e20fb91ae1

113121112431329 has 2 divisors, whose sum is σ = 113121112431330. Its totient is φ = 113121112431328.

The previous prime is 113121112431263. The next prime is 113121112431331. The reversal of 113121112431329 is 923134211121311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90951469775104 + 22169642656225 = 9536848^2 + 4708465^2 .

It is a cyclic number.

It is not a de Polignac number, because 113121112431329 - 244 = 95528926386913 is a prime.

It is a Sophie Germain prime.

Together with 113121112431331, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (113121112431529) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560556215664 + 56560556215665.

It is an arithmetic number, because the mean of its divisors is an integer number (56560556215665).

Almost surely, 2113121112431329 is an apocalyptic number.

It is an amenable number.

113121112431329 is a deficient number, since it is larger than the sum of its proper divisors (1).

113121112431329 is an equidigital number, since it uses as much as digits as its factorization.

113121112431329 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7776, while the sum is 35.

The spelling of 113121112431329 in words is "one hundred thirteen trillion, one hundred twenty-one billion, one hundred twelve million, four hundred thirty-one thousand, three hundred twenty-nine".