Base | Representation |
---|---|
bin | 10000011101100001011… |
… | …111101111110011111111 |
3 | 11000010212010011021221200 |
4 | 100131201133233303333 |
5 | 122013210300023403 |
6 | 2223401025230543 |
7 | 144504330203004 |
oct | 20354137576377 |
9 | 4003763137850 |
10 | 1131212111103 |
11 | 3a6820823038 |
12 | 1632a0792453 |
13 | 82899315279 |
14 | 3ca728b58ab |
15 | 1e65ac08ca3 |
hex | 107617efcff |
1131212111103 has 6 divisors (see below), whose sum is σ = 1633973049384. Its totient is φ = 754141407396.
The previous prime is 1131212111101. The next prime is 1131212111171. The reversal of 1131212111103 is 3011112121311.
It is not a de Polignac number, because 1131212111103 - 21 = 1131212111101 is a prime.
It is a super-2 number, since 2×11312121111032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131212111101) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 62845117275 + ... + 62845117292.
It is an arithmetic number, because the mean of its divisors is an integer number (272328841564).
Almost surely, 21131212111103 is an apocalyptic number.
1131212111103 is a deficient number, since it is larger than the sum of its proper divisors (502760938281).
1131212111103 is a wasteful number, since it uses less digits than its factorization.
1131212111103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 125690234573 (or 125690234570 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 18.
Adding to 1131212111103 its reverse (3011112121311), we get a palindrome (4142324232414).
The spelling of 1131212111103 in words is "one trillion, one hundred thirty-one billion, two hundred twelve million, one hundred eleven thousand, one hundred three".
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