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1131212111103 = 32125690234567
BaseRepresentation
bin10000011101100001011…
…111101111110011111111
311000010212010011021221200
4100131201133233303333
5122013210300023403
62223401025230543
7144504330203004
oct20354137576377
94003763137850
101131212111103
113a6820823038
121632a0792453
1382899315279
143ca728b58ab
151e65ac08ca3
hex107617efcff

1131212111103 has 6 divisors (see below), whose sum is σ = 1633973049384. Its totient is φ = 754141407396.

The previous prime is 1131212111101. The next prime is 1131212111171. The reversal of 1131212111103 is 3011112121311.

It is not a de Polignac number, because 1131212111103 - 21 = 1131212111101 is a prime.

It is a super-2 number, since 2×11312121111032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131212111101) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 62845117275 + ... + 62845117292.

It is an arithmetic number, because the mean of its divisors is an integer number (272328841564).

Almost surely, 21131212111103 is an apocalyptic number.

1131212111103 is a deficient number, since it is larger than the sum of its proper divisors (502760938281).

1131212111103 is a wasteful number, since it uses less digits than its factorization.

1131212111103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 125690234573 (or 125690234570 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 18.

Adding to 1131212111103 its reverse (3011112121311), we get a palindrome (4142324232414).

The spelling of 1131212111103 in words is "one trillion, one hundred thirty-one billion, two hundred twelve million, one hundred eleven thousand, one hundred three".

Divisors: 1 3 9 125690234567 377070703701 1131212111103