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1131212122103 = 7161601731729
BaseRepresentation
bin10000011101100001011…
…111110010011111110111
311000010212010011212001002
4100131201133302133313
5122013210300401403
62223401025353515
7144504330250040
oct20354137623767
94003763155032
101131212122103
113a6820830328
121632a079889b
138289931a28b
143ca728b98c7
151e65ac0c188
hex107617f27f7

1131212122103 has 4 divisors (see below), whose sum is σ = 1292813853840. Its totient is φ = 969610390368.

The previous prime is 1131212122097. The next prime is 1131212122123. The reversal of 1131212122103 is 3012212121311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131212122103 - 26 = 1131212122039 is a prime.

It is a super-3 number, since 3×11312121221033 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131212122123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80800865858 + ... + 80800865871.

It is an arithmetic number, because the mean of its divisors is an integer number (323203463460).

Almost surely, 21131212122103 is an apocalyptic number.

1131212122103 is a deficient number, since it is larger than the sum of its proper divisors (161601731737).

1131212122103 is an equidigital number, since it uses as much as digits as its factorization.

1131212122103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161601731736.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1131212122103 its reverse (3012212121311), we get a palindrome (4143424243414).

The spelling of 1131212122103 in words is "one trillion, one hundred thirty-one billion, two hundred twelve million, one hundred twenty-two thousand, one hundred three".

Divisors: 1 7 161601731729 1131212122103