Base | Representation |
---|---|
bin | 10101000100100000… |
… | …10100010111100001 |
3 | 1002012100202022012001 |
4 | 22202100110113201 |
5 | 141131400340223 |
6 | 5110254004001 |
7 | 550216305343 |
oct | 124220242741 |
9 | 32170668161 |
10 | 11312121313 |
11 | 4885441199 |
12 | 22384a6601 |
13 | 10b37aa70c |
14 | 79451b293 |
15 | 4631949ad |
hex | 2a24145e1 |
11312121313 has 2 divisors, whose sum is σ = 11312121314. Its totient is φ = 11312121312.
The previous prime is 11312121299. The next prime is 11312121323. The reversal of 11312121313 is 31312121311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8233203169 + 3078918144 = 90737^2 + 55488^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11312121313 is a prime.
It is not a weakly prime, because it can be changed into another prime (11312121323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656060656 + 5656060657.
It is an arithmetic number, because the mean of its divisors is an integer number (5656060657).
Almost surely, 211312121313 is an apocalyptic number.
It is an amenable number.
11312121313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312121313 is an equidigital number, since it uses as much as digits as its factorization.
11312121313 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 108, while the sum is 19.
Adding to 11312121313 its reverse (31312121311), we get a palindrome (42624242624).
The spelling of 11312121313 in words is "eleven billion, three hundred twelve million, one hundred twenty-one thousand, three hundred thirteen".
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