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113121223303 = 1122138343721
BaseRepresentation
bin110100101011010001…
…1001110001010000111
3101210222121112112211011
41221112203032022013
53323133013121203
6123544524223051
711113151350564
oct1512643161207
9353877475734
10113121223303
1143a79a88400
1219b1009aa87
13a88a0460ba
14569194386b
152e2113476d
hex1a568ce287

113121223303 has 12 divisors (see below), whose sum is σ = 124348515984. Its totient is φ = 102830314400.

The previous prime is 113121223279. The next prime is 113121223321. The reversal of 113121223303 is 303322121311.

It is not a de Polignac number, because 113121223303 - 213 = 113121215111 is a prime.

It is a super-2 number, since 2×1131212233032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113121223393) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2565483 + ... + 2609203.

It is an arithmetic number, because the mean of its divisors is an integer number (10362376332).

Almost surely, 2113121223303 is an apocalyptic number.

113121223303 is a deficient number, since it is larger than the sum of its proper divisors (11227292681).

113121223303 is a wasteful number, since it uses less digits than its factorization.

113121223303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65126 (or 65115 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 113121223303 its reverse (303322121311), we get a palindrome (416443344614).

The spelling of 113121223303 in words is "one hundred thirteen billion, one hundred twenty-one million, two hundred twenty-three thousand, three hundred three".

Divisors: 1 11 121 21383 43721 235213 480931 2587343 5290241 934886143 10283747573 113121223303