11312130301222 has 4 divisors (see below), whose sum is σ = 16968195451836. Its totient is φ = 5656065150610.

The previous prime is 11312130301207. The next prime is 11312130301253. The reversal of 11312130301222 is 22210303121311.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×11312130301222³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11312130301193 and 11312130301202.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2828032575304 + ... + 2828032575307.

It is an arithmetic number, because the mean of its divisors is an integer number (4242048862959).

Almost surely, 2^{11312130301222} is an apocalyptic number.

11312130301222 is a deficient number, since it is larger than the sum of its proper divisors (5656065150614).

11312130301222 is an equidigital number, since it uses as much as digits as its factorization.

11312130301222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5656065150613.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 11312130301222 its reverse (22210303121311), we get a palindrome (33522433422533).

The spelling of 11312130301222 in words is "eleven trillion, three hundred twelve billion, one hundred thirty million, three hundred one thousand, two hundred twenty-two".