Base | Representation |
---|---|
bin | 10000011101100001100… |
… | …011111100011001001011 |
3 | 11000010212012020012000102 |
4 | 100131201203330121023 |
5 | 122013211040224321 |
6 | 2223401105000015 |
7 | 144504342434216 |
oct | 20354143743113 |
9 | 4003765205012 |
10 | 1131213211211 |
11 | 3a6821404616 |
12 | 1632a102300b |
13 | 8289960bc15 |
14 | 3ca72ac077d |
15 | 1e65ad74c0b |
hex | 107618fc64b |
1131213211211 has 2 divisors, whose sum is σ = 1131213211212. Its totient is φ = 1131213211210.
The previous prime is 1131213211201. The next prime is 1131213211283. The reversal of 1131213211211 is 1121123121311.
It is a m-pointer prime, because the next prime (1131213211283) can be obtained adding 1131213211211 to its product of digits (72).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131213211211 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131213211201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565606605605 + 565606605606.
It is an arithmetic number, because the mean of its divisors is an integer number (565606605606).
Almost surely, 21131213211211 is an apocalyptic number.
1131213211211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131213211211 is an equidigital number, since it uses as much as digits as its factorization.
1131213211211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 72, while the sum is 20.
Adding to 1131213211211 its reverse (1121123121311), we get a palindrome (2252336332522).
The spelling of 1131213211211 in words is "one trillion, one hundred thirty-one billion, two hundred thirteen million, two hundred eleven thousand, two hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •