1131213300031 has 2 divisors, whose sum is σ = 1131213300032. Its totient is φ = 1131213300030.

The previous prime is 1131213299989. The next prime is 1131213300037. The reversal of 1131213300031 is 1300033121311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1131213300031 - 2¹⁵ = 1131213267263 is a prime.

It is a super-2 number, since 2×1131213300031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131213299981 and 1131213300008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131213300037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565606650015 + 565606650016.

It is an arithmetic number, because the mean of its divisors is an integer number (565606650016).

Almost surely, 2^{1131213300031} is an apocalyptic number.

1131213300031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131213300031 is an equidigital number, since it uses as much as digits as its factorization.

1131213300031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1131213300031 its reverse (1300033121311), we get a palindrome (2431246421342).

The spelling of 1131213300031 in words is "one trillion, one hundred thirty-one billion, two hundred thirteen million, three hundred thousand, thirty-one".