Base | Representation |
---|---|
bin | 1010010010011100111110… |
… | …1011010010010100100000 |
3 | 1111001102121000012010111221 |
4 | 2210213033223102110200 |
5 | 2440314222034340222 |
6 | 40020415555344424 |
7 | 2245163130013342 |
oct | 244471753222440 |
9 | 44042530163457 |
10 | 11312133121312 |
11 | 36714a32708a1 |
12 | 132844a5b2114 |
13 | 640963b5688a |
14 | 2b171dc69292 |
15 | 1493c41320c7 |
hex | a49cfad2520 |
11312133121312 has 48 divisors (see below), whose sum is σ = 22344090987960. Its totient is φ = 5637473830912.
The previous prime is 11312133121279. The next prime is 11312133121313. The reversal of 11312133121312 is 21312133121311.
It can be written as a sum of positive squares in 4 ways, for example, as 3664452604176 + 7647680517136 = 1914276^2 + 2765444^2 .
It is not an unprimeable number, because it can be changed into a prime (11312133121313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11414118 + ... + 12365530.
Almost surely, 211312133121312 is an apocalyptic number.
It is an amenable number.
11312133121312 is a deficient number, since it is larger than the sum of its proper divisors (11031957866648).
11312133121312 is an equidigital number, since it uses as much as digits as its factorization.
11312133121312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 952645 (or 952637 counting only the distinct ones).
The product of its digits is 648, while the sum is 25.
Adding to 11312133121312 its reverse (21312133121311), we get a palindrome (32624266242623).
Subtracting 11312133121312 from its reverse (21312133121311), we obtain a palindrome (9999999999999).
The spelling of 11312133121312 in words is "eleven trillion, three hundred twelve billion, one hundred thirty-three million, one hundred twenty-one thousand, three hundred twelve".
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