Base | Representation |
---|---|
bin | 10000011101100001100… |
… | …100010111011100110000 |
3 | 11000010212012102211000220 |
4 | 100131201210113130300 |
5 | 122013211102301112 |
6 | 2223401111213040 |
7 | 144504343405263 |
oct | 20354144273460 |
9 | 4003765384026 |
10 | 1131213322032 |
11 | 3a682147a902 |
12 | 1632a1077180 |
13 | 8289964a4b1 |
14 | 3ca72b0ccda |
15 | 1e65ad9798c |
hex | 10761917730 |
1131213322032 has 40 divisors (see below), whose sum is σ = 2922344408880. Its totient is φ = 377065516800.
The previous prime is 1131213322007. The next prime is 1131213322081. The reversal of 1131213322032 is 2302233121311.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a junction number, because it is equal to n+sod(n) for n = 1131213321993 and 1131213322011.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4253782 + ... + 4511882.
It is an arithmetic number, because the mean of its divisors is an integer number (73058610222).
Almost surely, 21131213322032 is an apocalyptic number.
1131213322032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1131213322032 is an abundant number, since it is smaller than the sum of its proper divisors (1791131086848).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131213322032 is a wasteful number, since it uses less digits than its factorization.
1131213322032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 349421 (or 349415 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1131213322032 its reverse (2302233121311), we get a palindrome (3433446443343).
The spelling of 1131213322032 in words is "one trillion, one hundred thirty-one billion, two hundred thirteen million, three hundred twenty-two thousand, thirty-two".
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