Base | Representation |
---|---|
bin | 11001101110001000011101… |
… | …010010111011001101000001 |
3 | 112211112021221200200221211101 |
4 | 121232020131102323031001 |
5 | 104311340001034024101 |
6 | 1040331120511414401 |
7 | 32553514156130023 |
oct | 3156103522731501 |
9 | 484467850627741 |
10 | 113121340142401 |
11 | 33053544496898 |
12 | 1082b80bb24401 |
13 | 4b173b1839c96 |
14 | 1dd1160150013 |
15 | d1282b8cb401 |
hex | 66e21d4bb341 |
113121340142401 has 2 divisors, whose sum is σ = 113121340142402. Its totient is φ = 113121340142400.
The previous prime is 113121340142347. The next prime is 113121340142501. The reversal of 113121340142401 is 104241043121311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99918116769025 + 13203223373376 = 9995905^2 + 3633624^2 .
It is a cyclic number.
It is not a de Polignac number, because 113121340142401 - 29 = 113121340141889 is a prime.
It is a super-2 number, since 2×1131213401424012 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 113121340142401.
It is not a weakly prime, because it can be changed into another prime (113121340142501) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560670071200 + 56560670071201.
It is an arithmetic number, because the mean of its divisors is an integer number (56560670071201).
Almost surely, 2113121340142401 is an apocalyptic number.
It is an amenable number.
113121340142401 is a deficient number, since it is larger than the sum of its proper divisors (1).
113121340142401 is an equidigital number, since it uses as much as digits as its factorization.
113121340142401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 113121340142401 its reverse (104241043121311), we get a palindrome (217362383263712).
The spelling of 113121340142401 in words is "one hundred thirteen trillion, one hundred twenty-one billion, three hundred forty million, one hundred forty-two thousand, four hundred one".
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