Base | Representation |
---|---|
bin | 10101000100100001… |
… | …00111110110110111 |
3 | 1002012100220100200201 |
4 | 22202100213312313 |
5 | 141131410414033 |
6 | 5110255421331 |
7 | 550220060155 |
oct | 124220476667 |
9 | 32170810621 |
10 | 11312201143 |
11 | 4885496171 |
12 | 2238524847 |
13 | 10b3807b59 |
14 | 79453c3d5 |
15 | 4631ad47d |
hex | 2a2427db7 |
11312201143 has 2 divisors, whose sum is σ = 11312201144. Its totient is φ = 11312201142.
The previous prime is 11312201111. The next prime is 11312201161. The reversal of 11312201143 is 34110221311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11312201143 - 25 = 11312201111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11312201143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11315201143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656100571 + 5656100572.
It is an arithmetic number, because the mean of its divisors is an integer number (5656100572).
Almost surely, 211312201143 is an apocalyptic number.
11312201143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312201143 is an equidigital number, since it uses as much as digits as its factorization.
11312201143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11312201143 its reverse (34110221311), we get a palindrome (45422422454).
The spelling of 11312201143 in words is "eleven billion, three hundred twelve million, two hundred one thousand, one hundred forty-three".
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