Base | Representation |
---|---|
bin | 110100101011010011… |
… | …0010011111010111101 |
3 | 101210222200001200222120 |
4 | 1221112212103322331 |
5 | 3323133220031331 |
6 | 123544553433153 |
7 | 11113161263322 |
oct | 1512646237275 |
9 | 353880050876 |
10 | 113122033341 |
11 | 43a7a490a59 |
12 | 19b1040b7b9 |
13 | a88a26aa05 |
14 | 5691ab4b49 |
15 | 2e21244796 |
hex | 1a56993ebd |
113122033341 has 8 divisors (see below), whose sum is σ = 153385808160. Its totient is φ = 74136473712.
The previous prime is 113122033307. The next prime is 113122033373. The reversal of 113122033341 is 143330221311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-113122033341 is a prime.
It is a super-3 number, since 3×1131220333413 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113122032341) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 319553590 + ... + 319553943.
It is an arithmetic number, because the mean of its divisors is an integer number (19173226020).
Almost surely, 2113122033341 is an apocalyptic number.
It is an amenable number.
113122033341 is a deficient number, since it is larger than the sum of its proper divisors (40263774819).
113122033341 is an equidigital number, since it uses as much as digits as its factorization.
113122033341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 639107595.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 113122033341 its reverse (143330221311), we get a palindrome (256452254652).
The spelling of 113122033341 in words is "one hundred thirteen billion, one hundred twenty-two million, thirty-three thousand, three hundred forty-one".
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