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11312240411413 is a prime number
BaseRepresentation
bin1010010010011101011000…
…0100100100001100010101
31111001102212111002000212101
42210213112010210030111
52440314432021131123
640020434351122101
72245165601660434
oct244472604441425
944042774060771
1011312240411413
1136715488914a7
12132847a513331
13640980150646
142b17301d711b
151493cd776aad
hexa49d6124315

11312240411413 has 2 divisors, whose sum is σ = 11312240411414. Its totient is φ = 11312240411412.

The previous prime is 11312240411347. The next prime is 11312240411497. The reversal of 11312240411413 is 31411404221311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11311907969124 + 332442289 = 3363318^2 + 18233^2 .

It is a cyclic number.

It is not a de Polignac number, because 11312240411413 - 213 = 11312240403221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312240411113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656120205706 + 5656120205707.

It is an arithmetic number, because the mean of its divisors is an integer number (5656120205707).

Almost surely, 211312240411413 is an apocalyptic number.

It is an amenable number.

11312240411413 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312240411413 is an equidigital number, since it uses as much as digits as its factorization.

11312240411413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 11312240411413 its reverse (31411404221311), we get a palindrome (42723644632724).

The spelling of 11312240411413 in words is "eleven trillion, three hundred twelve billion, two hundred forty million, four hundred eleven thousand, four hundred thirteen".