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113122404221311 is a prime number
BaseRepresentation
bin11001101110001001011100…
…101110000100000101111111
3112211112101200211221202200101
4121232021130232010011333
5104311344140440040221
61040331414242341531
732553552426503632
oct3156113456040577
9484471624852611
10113122404221311
1133053a400a7051
121082ba6835a8a7
134b17521121884
141dd12215bbc19
15d12890018d91
hex66e25cb8417f

113122404221311 has 2 divisors, whose sum is σ = 113122404221312. Its totient is φ = 113122404221310.

The previous prime is 113122404221279. The next prime is 113122404221369.

113122404221311 is nontrivially palindromic in base 10.

It is a weak prime.

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 113122404221311 - 25 = 113122404221279 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113122404221311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113122404221381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56561202110655 + 56561202110656.

It is an arithmetic number, because the mean of its divisors is an integer number (56561202110656).

Almost surely, 2113122404221311 is an apocalyptic number.

113122404221311 is a deficient number, since it is larger than the sum of its proper divisors (1).

113122404221311 is an equidigital number, since it uses as much as digits as its factorization.

113122404221311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 28.

It can be divided in two parts, 11312240 and 4221311, that added together give a palindrome (15533551).

The spelling of 113122404221311 in words is "one hundred thirteen trillion, one hundred twenty-two billion, four hundred four million, two hundred twenty-one thousand, three hundred eleven".