Base | Representation |
---|---|
bin | 1010010010011101011101… |
… | …1100000010111001111111 |
3 | 1111001102221002020010002221 |
4 | 2210213113130002321333 |
5 | 2440320003403444433 |
6 | 40020440530430211 |
7 | 2245166300621515 |
oct | 244472734027177 |
9 | 44042832203087 |
10 | 11312263343743 |
11 | 367155a82493a |
12 | 1328486132367 |
13 | 640984b1c67b |
14 | 2b17332864b5 |
15 | 1493d07a672d |
hex | a49d7702e7f |
11312263343743 has 2 divisors, whose sum is σ = 11312263343744. Its totient is φ = 11312263343742.
The previous prime is 11312263343707. The next prime is 11312263343747. The reversal of 11312263343743 is 34734336221311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11312263343743 - 229 = 11311726472831 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11312263343743.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312263343747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656131671871 + 5656131671872.
It is an arithmetic number, because the mean of its divisors is an integer number (5656131671872).
Almost surely, 211312263343743 is an apocalyptic number.
11312263343743 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312263343743 is an equidigital number, since it uses as much as digits as its factorization.
11312263343743 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 653184, while the sum is 43.
The spelling of 11312263343743 in words is "eleven trillion, three hundred twelve billion, two hundred sixty-three million, three hundred forty-three thousand, seven hundred forty-three".
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