Base | Representation |
---|---|
bin | 1010010010011101101000… |
… | …1111001101110100011111 |
3 | 1111001110001100121100202021 |
4 | 2210213122033031310133 |
5 | 2440320102414442343 |
6 | 40020445325241011 |
7 | 2245200411062044 |
oct | 244473217156437 |
9 | 44043040540667 |
10 | 11312310312223 |
11 | 3671584294a68 |
12 | 1328499a03167 |
13 | 640991785c7b |
14 | 2b17395d11cb |
15 | 1493d49830ed |
hex | a49da3cdd1f |
11312310312223 has 8 divisors (see below), whose sum is σ = 11345534311680. Its totient is φ = 11279134500480.
The previous prime is 11312310312217. The next prime is 11312310312269. The reversal of 11312310312223 is 32221301321311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11312310312223 - 225 = 11312276757791 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11312310312203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11576703 + ... + 12515776.
It is an arithmetic number, because the mean of its divisors is an integer number (1418191788960).
Almost surely, 211312310312223 is an apocalyptic number.
11312310312223 is a deficient number, since it is larger than the sum of its proper divisors (33223999457).
11312310312223 is an equidigital number, since it uses as much as digits as its factorization.
11312310312223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24093857.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11312310312223 its reverse (32221301321311), we get a palindrome (43533611633534).
The spelling of 11312310312223 in words is "eleven trillion, three hundred twelve billion, three hundred ten million, three hundred twelve thousand, two hundred twenty-three".
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