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11312333001121 is a prime number
BaseRepresentation
bin1010010010011101101110…
…0101110001000110100001
31111001110002221022002001211
42210213123211301012201
52440320124222013441
640020451455430121
72245201104660325
oct244473345610641
944043087262054
1011312333001121
113671596081519
1213284a5525341
1364099639b259
142b173c619985
151493d6965a81
hexa49db9711a1

11312333001121 has 2 divisors, whose sum is σ = 11312333001122. Its totient is φ = 11312333001120.

The previous prime is 11312333001107. The next prime is 11312333001209. The reversal of 11312333001121 is 12110033321311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10155279960225 + 1157053040896 = 3186735^2 + 1075664^2 .

It is a cyclic number.

It is not a de Polignac number, because 11312333001121 - 223 = 11312324612513 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11312333001092 and 11312333001101.

It is not a weakly prime, because it can be changed into another prime (11312343001121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656166500560 + 5656166500561.

It is an arithmetic number, because the mean of its divisors is an integer number (5656166500561).

Almost surely, 211312333001121 is an apocalyptic number.

It is an amenable number.

11312333001121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312333001121 is an equidigital number, since it uses as much as digits as its factorization.

11312333001121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 11312333001121 its reverse (12110033321311), we get a palindrome (23422366322432).

The spelling of 11312333001121 in words is "eleven trillion, three hundred twelve billion, three hundred thirty-three million, one thousand, one hundred twenty-one".