Base | Representation |
---|---|
bin | 10000011101100010110… |
… | …100000110101110001011 |
3 | 11000010220122202210120012 |
4 | 100131202310012232023 |
5 | 122013231430200120 |
6 | 2223403135222135 |
7 | 144505016155055 |
oct | 20354264065613 |
9 | 4003818683505 |
10 | 1131234225035 |
11 | 3a6832257612 |
12 | 1632a807794b |
13 | 828a0a88935 |
14 | 3ca757d08d5 |
15 | 1e65cb261c5 |
hex | 10762d06b8b |
1131234225035 has 4 divisors (see below), whose sum is σ = 1357481070048. Its totient is φ = 904987380024.
The previous prime is 1131234225007. The next prime is 1131234225071. The reversal of 1131234225035 is 5305224321311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1131234225035 - 26 = 1131234224971 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1131234224992 and 1131234225010.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113123422499 + ... + 113123422508.
It is an arithmetic number, because the mean of its divisors is an integer number (339370267512).
Almost surely, 21131234225035 is an apocalyptic number.
1131234225035 is a deficient number, since it is larger than the sum of its proper divisors (226246845013).
1131234225035 is an equidigital number, since it uses as much as digits as its factorization.
1131234225035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 226246845012.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 1131234225035 its reverse (5305224321311), we get a palindrome (6436458546346).
The spelling of 1131234225035 in words is "one trillion, one hundred thirty-one billion, two hundred thirty-four million, two hundred twenty-five thousand, thirty-five".
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