Base | Representation |
---|---|
bin | 10101000100100010… |
… | …01010010110000111 |
3 | 1002012101011112110201 |
4 | 22202101022112013 |
5 | 141131424424112 |
6 | 5110302431331 |
7 | 550221216052 |
oct | 124221122607 |
9 | 32171145421 |
10 | 11312342407 |
11 | 4885582313 |
12 | 2238592547 |
13 | 10b3857242 |
14 | 794577a99 |
15 | 4631da257 |
hex | 2a244a587 |
11312342407 has 2 divisors, whose sum is σ = 11312342408. Its totient is φ = 11312342406.
The previous prime is 11312342387. The next prime is 11312342423. The reversal of 11312342407 is 70424321311.
It is a strong prime.
It is an emirp because it is prime and its reverse (70424321311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11312342407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312342477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656171203 + 5656171204.
It is an arithmetic number, because the mean of its divisors is an integer number (5656171204).
Almost surely, 211312342407 is an apocalyptic number.
11312342407 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312342407 is an equidigital number, since it uses as much as digits as its factorization.
11312342407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 11312342407 its reverse (70424321311), we get a palindrome (81736663718).
The spelling of 11312342407 in words is "eleven billion, three hundred twelve million, three hundred forty-two thousand, four hundred seven".
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