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113124001322 = 256562000661
BaseRepresentation
bin110100101011010110…
…1110100011000101010
3101210222210202200112202
41221112231310120222
53323134221020242
6123545103540202
711113214101013
oct1512655643052
9353883680482
10113124001322
1143a80605592
1219b10bba662
13a88a7a96b7
14569206800a
152e214d2932
hex1a56b7462a

113124001322 has 4 divisors (see below), whose sum is σ = 169686001986. Its totient is φ = 56562000660.

The previous prime is 113124001301. The next prime is 113124001337. The reversal of 113124001322 is 223100421311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 112480415161 + 643586161 = 335381^2 + 25369^2 .

It is a junction number, because it is equal to n+sod(n) for n = 113124001294 and 113124001303.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28281000329 + ... + 28281000332.

Almost surely, 2113124001322 is an apocalyptic number.

113124001322 is a deficient number, since it is larger than the sum of its proper divisors (56562000664).

113124001322 is an equidigital number, since it uses as much as digits as its factorization.

113124001322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56562000663.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 113124001322 its reverse (223100421311), we get a palindrome (336224422633).

The spelling of 113124001322 in words is "one hundred thirteen billion, one hundred twenty-four million, one thousand, three hundred twenty-two".

Divisors: 1 2 56562000661 113124001322