Base | Representation |
---|---|
bin | 10101000100100010… |
… | …11000110000010011 |
3 | 1002012101021112102122 |
4 | 22202101120300103 |
5 | 141131433321202 |
6 | 5110304004455 |
7 | 550221553115 |
oct | 124221306023 |
9 | 32171245378 |
10 | 11312401427 |
11 | 4885612698 |
12 | 223860072b |
13 | 10b3878072 |
14 | 7945913b5 |
15 | 4631ec9a2 |
hex | 2a2458c13 |
11312401427 has 2 divisors, whose sum is σ = 11312401428. Its totient is φ = 11312401426.
The previous prime is 11312401417. The next prime is 11312401433. The reversal of 11312401427 is 72410421311.
It is a strong prime.
It is an emirp because it is prime and its reverse (72410421311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11312401427 - 210 = 11312400403 is a prime.
It is a super-3 number, since 3×113124014273 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11312401396 and 11312401405.
It is not a weakly prime, because it can be changed into another prime (11312401417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656200713 + 5656200714.
It is an arithmetic number, because the mean of its divisors is an integer number (5656200714).
Almost surely, 211312401427 is an apocalyptic number.
11312401427 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312401427 is an equidigital number, since it uses as much as digits as its factorization.
11312401427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 11312401427 its reverse (72410421311), we get a palindrome (83722822738).
The spelling of 11312401427 in words is "eleven billion, three hundred twelve million, four hundred one thousand, four hundred twenty-seven".
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