Base | Representation |
---|---|
bin | 110100101011010111… |
… | …0101000101000110001 |
3 | 101210222211011120010112 |
4 | 1221112232220220301 |
5 | 3323134244342340 |
6 | 123545112311105 |
7 | 11113215652001 |
oct | 1512656505061 |
9 | 353884146115 |
10 | 113124215345 |
11 | 43a80741369 |
12 | 19b110a2495 |
13 | a88a852c3b |
14 | 56920c2001 |
15 | 2e21526065 |
hex | 1a56ba8a31 |
113124215345 has 4 divisors (see below), whose sum is σ = 135749058420. Its totient is φ = 90499372272.
The previous prime is 113124215341. The next prime is 113124215411. The reversal of 113124215345 is 543512421311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 83692754209 + 29431461136 = 289297^2 + 171556^2 .
It is a cyclic number.
It is not a de Polignac number, because 113124215345 - 22 = 113124215341 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113124215341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11312421530 + ... + 11312421539.
It is an arithmetic number, because the mean of its divisors is an integer number (33937264605).
Almost surely, 2113124215345 is an apocalyptic number.
It is an amenable number.
113124215345 is a deficient number, since it is larger than the sum of its proper divisors (22624843075).
113124215345 is an equidigital number, since it uses as much as digits as its factorization.
113124215345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22624843074.
The product of its digits is 14400, while the sum is 32.
Adding to 113124215345 its reverse (543512421311), we get a palindrome (656636636656).
The spelling of 113124215345 in words is "one hundred thirteen billion, one hundred twenty-four million, two hundred fifteen thousand, three hundred forty-five".
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