11312433203051 has 2 divisors, whose sum is σ = 11312433203052. Its totient is φ = 11312433203050.

The previous prime is 11312433203021. The next prime is 11312433203053. The reversal of 11312433203051 is 15030233421311.

It is a strong prime.

It is an emirp because it is prime and its reverse (15030233421311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11312433203051 - 2²² = 11312429008747 is a prime.

It is a super-2 number, since 2×11312433203051² (a number of 27 digits) contains 22 as substring.

Together with 11312433203053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11312433203053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656216601525 + 5656216601526.

It is an arithmetic number, because the mean of its divisors is an integer number (5656216601526).

Almost surely, 2^{11312433203051} is an apocalyptic number.

11312433203051 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312433203051 is an equidigital number, since it uses as much as digits as its factorization.

11312433203051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 11312433203051 its reverse (15030233421311), we get a palindrome (26342666624362).

The spelling of 11312433203051 in words is "eleven trillion, three hundred twelve billion, four hundred thirty-three million, two hundred three thousand, fifty-one".