113124340231 has 4 divisors (see below), whose sum is σ = 129284960272. Its totient is φ = 96963720192.

The previous prime is 113124340183. The next prime is 113124340247. The reversal of 113124340231 is 132043421311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113124340231 - 2¹¹ = 113124338183 is a prime.

It is a super-2 number, since 2×113124340231² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113124340196 and 113124340205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113124349231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8080310010 + ... + 8080310023.

It is an arithmetic number, because the mean of its divisors is an integer number (32321240068).

Almost surely, 2^113124340231 is an apocalyptic number.

113124340231 is a deficient number, since it is larger than the sum of its proper divisors (16160620041).

113124340231 is an equidigital number, since it uses as much as digits as its factorization.

113124340231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16160620040.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 113124340231 its reverse (132043421311), we get a palindrome (245167761542).

The spelling of 113124340231 in words is "one hundred thirteen billion, one hundred twenty-four million, three hundred forty thousand, two hundred thirty-one".