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11312435320213 is a prime number
BaseRepresentation
bin1010010010011110000110…
…1100000101010110010101
31111001110101001211102110211
42210213201230011112111
52440320331420221323
640020505552445421
72245203456451606
oct244474154052625
944043331742424
1011312435320213
113671638907355
121328513849871
136409b16444b1
142b174c051dad
151493e092770d
hexa49e1b05595

11312435320213 has 2 divisors, whose sum is σ = 11312435320214. Its totient is φ = 11312435320212.

The previous prime is 11312435320189. The next prime is 11312435320339. The reversal of 11312435320213 is 31202353421311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8996508338724 + 2315926981489 = 2999418^2 + 1521817^2 .

It is a cyclic number.

It is not a de Polignac number, because 11312435320213 - 217 = 11312435189141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312435320013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656217660106 + 5656217660107.

It is an arithmetic number, because the mean of its divisors is an integer number (5656217660107).

Almost surely, 211312435320213 is an apocalyptic number.

It is an amenable number.

11312435320213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312435320213 is an equidigital number, since it uses as much as digits as its factorization.

11312435320213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 11312435320213 its reverse (31202353421311), we get a palindrome (42514788741524).

The spelling of 11312435320213 in words is "eleven trillion, three hundred twelve billion, four hundred thirty-five million, three hundred twenty thousand, two hundred thirteen".