1131253433 has 4 divisors (see below), whose sum is σ = 1150427280. Its totient is φ = 1112079588.

The previous prime is 1131253421. The next prime is 1131253451. The reversal of 1131253433 is 3343521311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1131253433 - 2²⁰ = 1130204857 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1131253493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9586835 + ... + 9586952.

It is an arithmetic number, because the mean of its divisors is an integer number (287606820).

Almost surely, 2^1131253433 is an apocalyptic number.

It is an amenable number.

1131253433 is a deficient number, since it is larger than the sum of its proper divisors (19173847).

1131253433 is an equidigital number, since it uses as much as digits as its factorization.

1131253433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19173846.

The product of its digits is 3240, while the sum is 26.

The square root of 1131253433 is about 33634.1111522216. Note that the first 4 decimals coincide. The cubic root of 1131253433 is about 1041.9654133742.

Adding to 1131253433 its reverse (3343521311), we get a palindrome (4474774744).

The spelling of 1131253433 in words is "one billion, one hundred thirty-one million, two hundred fifty-three thousand, four hundred thirty-three".