Base | Representation |
---|---|
bin | 1010010010100000001101… |
… | …0110001111100000110110 |
3 | 1111001111211102102010222120 |
4 | 2210220003112033200312 |
5 | 2440323011001120042 |
6 | 40021042004140410 |
7 | 2245223454356001 |
oct | 244500326174066 |
9 | 44044742363876 |
10 | 11313000020022 |
11 | 36718a8644708 |
12 | 1328650997706 |
13 | 640a716307ac |
14 | 2b17a304a538 |
15 | 1494252c0dec |
hex | a4a0358f836 |
11313000020022 has 64 divisors (see below), whose sum is σ = 22980336180480. Its totient is φ = 3712149264384.
The previous prime is 11313000020017. The next prime is 11313000020081. The reversal of 11313000020022 is 22002000031311.
It is a junction number, because it is equal to n+sod(n) for n = 11313000019983 and 11313000020010.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 738005254 + ... + 738020582.
It is an arithmetic number, because the mean of its divisors is an integer number (359067752820).
Almost surely, 211313000020022 is an apocalyptic number.
11313000020022 is an abundant number, since it is smaller than the sum of its proper divisors (11667336160458).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313000020022 is a wasteful number, since it uses less digits than its factorization.
11313000020022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18557.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 11313000020022 its reverse (22002000031311), we get a palindrome (33315000051333).
The spelling of 11313000020022 in words is "eleven trillion, three hundred thirteen billion, twenty thousand, twenty-two".
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