Base | Representation |
---|---|
bin | 11001101110010000100010… |
… | …101011001101111001110001 |
3 | 112211120010100122000020020111 |
4 | 121232100202223031321301 |
5 | 104312010240201043441 |
6 | 1040335114110141321 |
7 | 32554242236406463 |
oct | 3156204253157161 |
9 | 484503318006214 |
10 | 113130020331121 |
11 | 33057199202082 |
12 | 10831432ab1841 |
13 | 4b18165c73c21 |
14 | 1dd1744cb6133 |
15 | d12b88984081 |
hex | 66e422acde71 |
113130020331121 has 8 divisors (see below), whose sum is σ = 114312387588840. Its totient is φ = 111947981203968.
The previous prime is 113130020331113. The next prime is 113130020331127. The reversal of 113130020331121 is 121133020031311.
It can be written as a sum of positive squares in 4 ways, for example, as 12525830464225 + 100604189866896 = 3539185^2 + 10030164^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113130020331121 - 23 = 113130020331113 is a prime.
It is a super-2 number, since 2×1131300203311212 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113130020331092 and 113130020331101.
It is not an unprimeable number, because it can be changed into a prime (113130020331127) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81339466 + ... + 82718611.
It is an arithmetic number, because the mean of its divisors is an integer number (14289048448605).
Almost surely, 2113130020331121 is an apocalyptic number.
It is an amenable number.
113130020331121 is a deficient number, since it is larger than the sum of its proper divisors (1182367257719).
113130020331121 is an equidigital number, since it uses as much as digits as its factorization.
113130020331121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 164065283.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 113130020331121 its reverse (121133020031311), we get a palindrome (234263040362432).
The spelling of 113130020331121 in words is "one hundred thirteen trillion, one hundred thirty billion, twenty million, three hundred thirty-one thousand, one hundred twenty-one".
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