Base | Representation |
---|---|
bin | 10101000100100111… |
… | …01101110101000001 |
3 | 1002012102102120000200 |
4 | 22202103231311001 |
5 | 141132112341113 |
6 | 5110325035413 |
7 | 550230005241 |
oct | 124223556501 |
9 | 32172376020 |
10 | 11313012033 |
11 | 488599a424 |
12 | 2238855b69 |
13 | 10b3a2cc7b |
14 | 7946adb21 |
15 | 4632bd873 |
hex | 2a24edd41 |
11313012033 has 6 divisors (see below), whose sum is σ = 16341017394. Its totient is φ = 7542008016.
The previous prime is 11313012031. The next prime is 11313012037. The reversal of 11313012033 is 33021031311.
It is a happy number.
It can be written as a sum of positive squares in only one way, i.e., 11306494224 + 6517809 = 106332^2 + 2553^2 .
It is not a de Polignac number, because 11313012033 - 21 = 11313012031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11313011997 and 11313012015.
It is not an unprimeable number, because it can be changed into a prime (11313012031) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 628500660 + ... + 628500677.
It is an arithmetic number, because the mean of its divisors is an integer number (2723502899).
Almost surely, 211313012033 is an apocalyptic number.
It is an amenable number.
11313012033 is a deficient number, since it is larger than the sum of its proper divisors (5028005361).
11313012033 is a wasteful number, since it uses less digits than its factorization.
11313012033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1257001343 (or 1257001340 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 18.
Adding to 11313012033 its reverse (33021031311), we get a palindrome (44334043344).
The spelling of 11313012033 in words is "eleven billion, three hundred thirteen million, twelve thousand, thirty-three".
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