Base | Representation |
---|---|
bin | 10101000100100111… |
… | …01101110110000111 |
3 | 1002012102102120010021 |
4 | 22202103231312013 |
5 | 141132112341403 |
6 | 5110325040011 |
7 | 550230005401 |
oct | 124223556607 |
9 | 32172376107 |
10 | 11313012103 |
11 | 488599a488 |
12 | 2238856007 |
13 | 10b3a30003 |
14 | 7946adb71 |
15 | 4632bd8bd |
hex | 2a24edd87 |
11313012103 has 2 divisors, whose sum is σ = 11313012104. Its totient is φ = 11313012102.
The previous prime is 11313012077. The next prime is 11313012157. The reversal of 11313012103 is 30121031311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11313012103 - 217 = 11312881031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313012163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656506051 + 5656506052.
It is an arithmetic number, because the mean of its divisors is an integer number (5656506052).
Almost surely, 211313012103 is an apocalyptic number.
11313012103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313012103 is an equidigital number, since it uses as much as digits as its factorization.
11313012103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11313012103 its reverse (30121031311), we get a palindrome (41434043414).
The spelling of 11313012103 in words is "eleven billion, three hundred thirteen million, twelve thousand, one hundred three".
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