1131301320133 has 2 divisors, whose sum is σ = 1131301320134. Its totient is φ = 1131301320132.

The previous prime is 1131301320067. The next prime is 1131301320139. The reversal of 1131301320133 is 3310231031311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 958709264769 + 172592055364 = 979137^2 + 415442^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131301320133 - 2²¹ = 1131299222981 is a prime.

It is a super-2 number, since 2×1131301320133² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131301320139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565650660066 + 565650660067.

It is an arithmetic number, because the mean of its divisors is an integer number (565650660067).

Almost surely, 2^{1131301320133} is an apocalyptic number.

It is an amenable number.

1131301320133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131301320133 is an equidigital number, since it uses as much as digits as its factorization.

1131301320133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 1131301320133 its reverse (3310231031311), we get a palindrome (4441532351444).

The spelling of 1131301320133 in words is "one trillion, one hundred thirty-one billion, three hundred one million, three hundred twenty thousand, one hundred thirty-three".