11313025213440 has 176 divisors, whose sum is σ = 36189410175360. Its totient is φ = 3016356003840.

The previous prime is 11313025213433. The next prime is 11313025213453. The reversal of 11313025213440 is 4431252031311.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 11313025213398 and 11313025213407.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 109910800 + ... + 110013680.

Almost surely, 2^{11313025213440} is an apocalyptic number.

11313025213440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313025213440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18094705087680).

11313025213440 is an abundant number, since it is smaller than the sum of its proper divisors (24876384961920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313025213440 is a wasteful number, since it uses less digits than its factorization.

11313025213440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110068 (or 110050 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 11313025213440 its reverse (4431252031311), we get a palindrome (15744277244751).

The spelling of 11313025213440 in words is "eleven trillion, three hundred thirteen billion, twenty-five million, two hundred thirteen thousand, four hundred forty".