11313033040041 has 8 divisors (see below), whose sum is σ = 15084104370720. Its totient is φ = 7541991868032.

The previous prime is 11313033040037. The next prime is 11313033040117. The reversal of 11313033040041 is 14004033031311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11313033040041 - 2² = 11313033040037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11313033039993 and 11313033040020.

It is not an unprimeable number, because it can be changed into a prime (11313033040241) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6649375 + ... + 8175588.

It is an arithmetic number, because the mean of its divisors is an integer number (1885513046340).

Almost surely, 2^{11313033040041} is an apocalyptic number.

It is an amenable number.

11313033040041 is a deficient number, since it is larger than the sum of its proper divisors (3771071330679).

11313033040041 is a wasteful number, since it uses less digits than its factorization.

11313033040041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15079335.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 11313033040041 its reverse (14004033031311), we get a palindrome (25317066071352).

The spelling of 11313033040041 in words is "eleven trillion, three hundred thirteen billion, thirty-three million, forty thousand, forty-one".