Base | Representation |
---|---|
bin | 1010010010100000010101… |
… | …0100001101000011110101 |
3 | 1111001111220201112202001001 |
4 | 2210220011110031003311 |
5 | 2440323042424240432 |
6 | 40021045144003301 |
7 | 2245224335133334 |
oct | 244500524150365 |
9 | 44044821482031 |
10 | 11313033040117 |
11 | 3671915248146 |
12 | 132865ba60531 |
13 | 640a78422303 |
14 | 2b17a75a3d1b |
15 | 1494281449e7 |
hex | a4a0550d0f5 |
11313033040117 has 2 divisors, whose sum is σ = 11313033040118. Its totient is φ = 11313033040116.
The previous prime is 11313033040037. The next prime is 11313033040129. The reversal of 11313033040117 is 71104033031311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7391389501521 + 3921643538596 = 2718711^2 + 1980314^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11313033040117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313033010117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656516520058 + 5656516520059.
It is an arithmetic number, because the mean of its divisors is an integer number (5656516520059).
Almost surely, 211313033040117 is an apocalyptic number.
It is an amenable number.
11313033040117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313033040117 is an equidigital number, since it uses as much as digits as its factorization.
11313033040117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 11313033040117 its reverse (71104033031311), we get a palindrome (82417066071428).
The spelling of 11313033040117 in words is "eleven trillion, three hundred thirteen billion, thirty-three million, forty thousand, one hundred seventeen".
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