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113130541330 = 2511313054133
BaseRepresentation
bin110100101011100011…
…0110001000100010010
3101211000021001221202021
41221113012301010102
53323142404310310
6123545500042054
711113323510052
oct1512706610422
9354007057667
10113130541330
1143a84272154
1219b1323332a
13a88bc59421
145692c8b562
152e21d755da
hex1a571b1112

113130541330 has 8 divisors (see below), whose sum is σ = 203634974412. Its totient is φ = 45252216528.

The previous prime is 113130541273. The next prime is 113130541357. The reversal of 113130541330 is 33145031311.

It can be written as a sum of positive squares in 2 ways, for example, as 95623811361 + 17506729969 = 309231^2 + 132313^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 113130541295 and 113130541304.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5656527057 + ... + 5656527076.

Almost surely, 2113130541330 is an apocalyptic number.

113130541330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113130541330 is a deficient number, since it is larger than the sum of its proper divisors (90504433082).

113130541330 is a wasteful number, since it uses less digits than its factorization.

113130541330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11313054140.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 113130541330 its reverse (33145031311), we get a palindrome (146275572641).

The spelling of 113130541330 in words is "one hundred thirteen billion, one hundred thirty million, five hundred forty-one thousand, three hundred thirty".

Divisors: 1 2 5 10 11313054133 22626108266 56565270665 113130541330