Base | Representation |
---|---|
bin | 1010010010100000100101… |
… | …0100011110101100100111 |
3 | 1111001112002101221220012011 |
4 | 2210220021110132230213 |
5 | 2440323212124034343 |
6 | 40021055543535051 |
7 | 2245226112146533 |
oct | 244501124365447 |
9 | 44045071856164 |
10 | 11313100221223 |
11 | 367194a163319 |
12 | 132867a45a487 |
13 | 640a89314a48 |
14 | 2b17b2490bc3 |
15 | 14942deb529d |
hex | a4a0951eb27 |
11313100221223 has 2 divisors, whose sum is σ = 11313100221224. Its totient is φ = 11313100221222.
The previous prime is 11313100221211. The next prime is 11313100221257. The reversal of 11313100221223 is 32212200131311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11313100221223 - 29 = 11313100220711 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11313100221194 and 11313100221203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313100221263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656550110611 + 5656550110612.
It is an arithmetic number, because the mean of its divisors is an integer number (5656550110612).
Almost surely, 211313100221223 is an apocalyptic number.
11313100221223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313100221223 is an equidigital number, since it uses as much as digits as its factorization.
11313100221223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 11313100221223 its reverse (32212200131311), we get a palindrome (43525300352534).
The spelling of 11313100221223 in words is "eleven trillion, three hundred thirteen billion, one hundred million, two hundred twenty-one thousand, two hundred twenty-three".
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