Base | Representation |
---|---|
bin | 10000011101100111010… |
… | …110000010100111100101 |
3 | 11000011002221210020202111 |
4 | 100131213112002213211 |
5 | 122013410404324424 |
6 | 2223414452241021 |
7 | 144506631201622 |
oct | 20354726024745 |
9 | 4004087706674 |
10 | 1131310229989 |
11 | 3a687114a225 |
12 | 163309610171 |
13 | 828b374a794 |
14 | 3ca81937349 |
15 | 1e66463b194 |
hex | 107675829e5 |
1131310229989 has 2 divisors, whose sum is σ = 1131310229990. Its totient is φ = 1131310229988.
The previous prime is 1131310229941. The next prime is 1131310230049. The reversal of 1131310229989 is 9899220131311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 892401408900 + 238908821089 = 944670^2 + 488783^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131310229989 - 211 = 1131310227941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131310829989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565655114994 + 565655114995.
It is an arithmetic number, because the mean of its divisors is an integer number (565655114995).
Almost surely, 21131310229989 is an apocalyptic number.
It is an amenable number.
1131310229989 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131310229989 is an equidigital number, since it uses as much as digits as its factorization.
1131310229989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209952, while the sum is 49.
The spelling of 1131310229989 in words is "one trillion, one hundred thirty-one billion, three hundred ten million, two hundred twenty-nine thousand, nine hundred eighty-nine".
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