11313104312131 has 8 divisors (see below), whose sum is σ = 11993801610960. Its totient is φ = 10634098188288.

The previous prime is 11313104312113. The next prime is 11313104312143. The reversal of 11313104312131 is 13121340131311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11313104312131 - 2⁵ = 11313104312099 is a prime.

It is a super-2 number, since 2×11313104312131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11313104312096 and 11313104312105.

It is not an unprimeable number, because it can be changed into a prime (11313104312171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 422779966 + ... + 422806723.

It is an arithmetic number, because the mean of its divisors is an integer number (1499225201370).

Almost surely, 2^{11313104312131} is an apocalyptic number.

11313104312131 is a deficient number, since it is larger than the sum of its proper divisors (680697298829).

11313104312131 is an equidigital number, since it uses as much as digits as its factorization.

11313104312131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 845587493.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 11313104312131 its reverse (13121340131311), we get a palindrome (24434444443442).

The spelling of 11313104312131 in words is "eleven trillion, three hundred thirteen billion, one hundred four million, three hundred twelve thousand, one hundred thirty-one".