Base | Representation |
---|---|
bin | 10000011101100111011… |
… | …100111000001000110011 |
3 | 11000011010002011022000202 |
4 | 100131213130320020303 |
5 | 122013411334201232 |
6 | 2223414554505415 |
7 | 144506652344423 |
oct | 20354734701063 |
9 | 4004102138022 |
10 | 1131312022067 |
11 | 3a6872163687 |
12 | 16330a13526b |
13 | 828b3c27396 |
14 | 3ca81c82483 |
15 | 1e664892162 |
hex | 10767738233 |
1131312022067 has 2 divisors, whose sum is σ = 1131312022068. Its totient is φ = 1131312022066.
The previous prime is 1131312021989. The next prime is 1131312022069. The reversal of 1131312022067 is 7602202131311.
It is a strong prime.
It is an emirp because it is prime and its reverse (7602202131311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1131312022067 - 28 = 1131312021811 is a prime.
Together with 1131312022069, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1131312022069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565656011033 + 565656011034.
It is an arithmetic number, because the mean of its divisors is an integer number (565656011034).
Almost surely, 21131312022067 is an apocalyptic number.
1131312022067 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131312022067 is an equidigital number, since it uses as much as digits as its factorization.
1131312022067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 29.
Adding to 1131312022067 its reverse (7602202131311), we get a palindrome (8733514153378).
The spelling of 1131312022067 in words is "one trillion, one hundred thirty-one billion, three hundred twelve million, twenty-two thousand, sixty-seven".
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