Base | Representation |
---|---|
bin | 11001101110010001101001… |
… | …001000001001011010000011 |
3 | 112211120020102000010111011111 |
4 | 121232101221020021122003 |
5 | 104312020200243220003 |
6 | 1040335431252224151 |
7 | 32554313441221300 |
oct | 3156215110113203 |
9 | 484506360114144 |
10 | 113131202320003 |
11 | 3305774542689a |
12 | 1083170290b057 |
13 | 4b182c3b0032a |
14 | 1dd1817c780a7 |
15 | d12c07612e6d |
hex | 66e469209683 |
113131202320003 has 24 divisors (see below), whose sum is σ = 139351077437184. Its totient is φ = 91260134380800.
The previous prime is 113131202319923. The next prime is 113131202320043. The reversal of 113131202320003 is 300023202131311.
It is a de Polignac number, because none of the positive numbers 2k-113131202320003 is a prime.
It is a super-2 number, since 2×1131312023200032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113131202320043) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10188958 + ... + 18168028.
It is an arithmetic number, because the mean of its divisors is an integer number (5806294893216).
Almost surely, 2113131202320003 is an apocalyptic number.
113131202320003 is a deficient number, since it is larger than the sum of its proper divisors (26219875117181).
113131202320003 is a wasteful number, since it uses less digits than its factorization.
113131202320003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7996123 (or 7996116 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 113131202320003 its reverse (300023202131311), we get a palindrome (413154404451314).
The spelling of 113131202320003 in words is "one hundred thirteen trillion, one hundred thirty-one billion, two hundred two million, three hundred twenty thousand, three".
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