Base | Representation |
---|---|
bin | 10000011101100111011… |
… | …101111110101110110111 |
3 | 11000011010002200222200020 |
4 | 100131213131332232313 |
5 | 122013411422424343 |
6 | 2223415005020223 |
7 | 144506654660433 |
oct | 20354735765667 |
9 | 4004102628606 |
10 | 1131312311223 |
11 | 3a6872340956 |
12 | 16330a254673 |
13 | 828b3cc8b93 |
14 | 3ca81d199c3 |
15 | 1e6648ecb83 |
hex | 1076777ebb7 |
1131312311223 has 4 divisors (see below), whose sum is σ = 1508416414968. Its totient is φ = 754208207480.
The previous prime is 1131312311209. The next prime is 1131312311231. The reversal of 1131312311223 is 3221132131311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1131312311223 - 28 = 1131312310967 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1131312311193 and 1131312311202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131312311273) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188552051868 + ... + 188552051873.
It is an arithmetic number, because the mean of its divisors is an integer number (377104103742).
Almost surely, 21131312311223 is an apocalyptic number.
1131312311223 is a deficient number, since it is larger than the sum of its proper divisors (377104103745).
1131312311223 is an equidigital number, since it uses as much as digits as its factorization.
1131312311223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 377104103744.
The product of its digits is 648, while the sum is 24.
Adding to 1131312311223 its reverse (3221132131311), we get a palindrome (4352444442534).
The spelling of 1131312311223 in words is "one trillion, one hundred thirty-one billion, three hundred twelve million, three hundred eleven thousand, two hundred twenty-three".
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