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113131231197233 is a prime number
BaseRepresentation
bin11001101110010001101010…
…110110010011100000110001
3112211120020111000110121021112
4121232101222312103200301
5104312020230141302413
61040335434203203105
732554314241532414
oct3156215266234061
9484506430417245
10113131231197233
113305775a75a777
1210831710516495
134b182c9aa1252
141dd181ba33b7b
15d12c09e192a8
hex66e46ad93831

113131231197233 has 2 divisors, whose sum is σ = 113131231197234. Its totient is φ = 113131231197232.

The previous prime is 113131231197221. The next prime is 113131231197241. The reversal of 113131231197233 is 332791132131311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66046698655744 + 47084532541489 = 8126912^2 + 6861817^2 .

It is a cyclic number.

It is not a de Polignac number, because 113131231197233 - 212 = 113131231193137 is a prime.

It is not a weakly prime, because it can be changed into another prime (113131231197133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565615598616 + 56565615598617.

It is an arithmetic number, because the mean of its divisors is an integer number (56565615598617).

Almost surely, 2113131231197233 is an apocalyptic number.

It is an amenable number.

113131231197233 is a deficient number, since it is larger than the sum of its proper divisors (1).

113131231197233 is an equidigital number, since it uses as much as digits as its factorization.

113131231197233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 61236, while the sum is 41.

The spelling of 113131231197233 in words is "one hundred thirteen trillion, one hundred thirty-one billion, two hundred thirty-one million, one hundred ninety-seven thousand, two hundred thirty-three".