Base | Representation |
---|---|
bin | 11001101110010001101010… |
… | …110110011011100000011111 |
3 | 112211120020111000112021012111 |
4 | 121232101222312123200133 |
5 | 104312020230143324413 |
6 | 1040335434204014451 |
7 | 32554314242030041 |
oct | 3156215266334037 |
9 | 484506430467174 |
10 | 113131231229983 |
11 | 3305775a78233a |
12 | 10831710531427 |
13 | 4b182c9ab3125 |
14 | 1dd181ba41a91 |
15 | d12c09e23d3d |
hex | 66e46ad9b81f |
113131231229983 has 2 divisors, whose sum is σ = 113131231229984. Its totient is φ = 113131231229982.
The previous prime is 113131231229963. The next prime is 113131231230001. The reversal of 113131231229983 is 389922132131311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113131231229983 - 213 = 113131231221791 is a prime.
It is a super-2 number, since 2×1131312312299832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113131231229963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565615614991 + 56565615614992.
It is an arithmetic number, because the mean of its divisors is an integer number (56565615614992).
Almost surely, 2113131231229983 is an apocalyptic number.
113131231229983 is a deficient number, since it is larger than the sum of its proper divisors (1).
113131231229983 is an equidigital number, since it uses as much as digits as its factorization.
113131231229983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 419904, while the sum is 49.
The spelling of 113131231229983 in words is "one hundred thirteen trillion, one hundred thirty-one billion, two hundred thirty-one million, two hundred twenty-nine thousand, nine hundred eighty-three".
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