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113131231229983 is a prime number
BaseRepresentation
bin11001101110010001101010…
…110110011011100000011111
3112211120020111000112021012111
4121232101222312123200133
5104312020230143324413
61040335434204014451
732554314242030041
oct3156215266334037
9484506430467174
10113131231229983
113305775a78233a
1210831710531427
134b182c9ab3125
141dd181ba41a91
15d12c09e23d3d
hex66e46ad9b81f

113131231229983 has 2 divisors, whose sum is σ = 113131231229984. Its totient is φ = 113131231229982.

The previous prime is 113131231229963. The next prime is 113131231230001. The reversal of 113131231229983 is 389922132131311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113131231229983 - 213 = 113131231221791 is a prime.

It is a super-2 number, since 2×1131312312299832 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113131231229963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565615614991 + 56565615614992.

It is an arithmetic number, because the mean of its divisors is an integer number (56565615614992).

Almost surely, 2113131231229983 is an apocalyptic number.

113131231229983 is a deficient number, since it is larger than the sum of its proper divisors (1).

113131231229983 is an equidigital number, since it uses as much as digits as its factorization.

113131231229983 is an evil number, because the sum of its binary digits is even.

The product of its digits is 419904, while the sum is 49.

The spelling of 113131231229983 in words is "one hundred thirteen trillion, one hundred thirty-one billion, two hundred thirty-one million, two hundred twenty-nine thousand, nine hundred eighty-three".