Base | Representation |
---|---|
bin | 10101000100101000… |
… | …01001010010111101 |
3 | 1002012102122021100122 |
4 | 22202110021102331 |
5 | 141132124441131 |
6 | 5110331304325 |
7 | 550230654245 |
oct | 124224112275 |
9 | 32172567318 |
10 | 11313124541 |
11 | 4885a66a04 |
12 | 22388ab0a5 |
13 | 10b3a6c244 |
14 | 7946dcb25 |
15 | 4632e1d7b |
hex | 2a25094bd |
11313124541 has 4 divisors (see below), whose sum is σ = 11313761472. Its totient is φ = 11312487612.
The previous prime is 11313124523. The next prime is 11313124549. The reversal of 11313124541 is 14542131311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11313124541 - 230 = 10239382717 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 11313124541.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313124549) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 291035 + ... + 327608.
It is an arithmetic number, because the mean of its divisors is an integer number (2828440368).
Almost surely, 211313124541 is an apocalyptic number.
It is an amenable number.
11313124541 is a deficient number, since it is larger than the sum of its proper divisors (636931).
11313124541 is an equidigital number, since it uses as much as digits as its factorization.
11313124541 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 636930.
The product of its digits is 1440, while the sum is 26.
Adding to 11313124541 its reverse (14542131311), we get a palindrome (25855255852).
The spelling of 11313124541 in words is "eleven billion, three hundred thirteen million, one hundred twenty-four thousand, five hundred forty-one".
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