1131313000130 has 16 divisors (see below), whose sum is σ = 2060897900544. Its totient is φ = 447073088880.

The previous prime is 1131313000121. The next prime is 1131313000187. The reversal of 1131313000130 is 310003131311.

It is a junction number, because it is equal to n+sod(n) for n = 1131313000099 and 1131313000108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 681513026 + ... + 681514685.

It is an arithmetic number, because the mean of its divisors is an integer number (128806118784).

Almost surely, 2^{1131313000130} is an apocalyptic number.

1131313000130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1131313000130 is a deficient number, since it is larger than the sum of its proper divisors (929584900414).

1131313000130 is a wasteful number, since it uses less digits than its factorization.

1131313000130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1363027801.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1131313000130 its reverse (310003131311), we get a palindrome (1441316131441).

The spelling of 1131313000130 in words is "one trillion, one hundred thirty-one billion, three hundred thirteen million, one hundred thirty", and thus it is an aban number.