Base | Representation |
---|---|
bin | 10101000100101000… |
… | …01011000111111111 |
3 | 1002012102122122122001 |
4 | 22202110023013333 |
5 | 141132130211111 |
6 | 5110331403131 |
7 | 550231015135 |
oct | 124224130777 |
9 | 32172578561 |
10 | 11313132031 |
11 | 4885a715a3 |
12 | 22388b34a7 |
13 | 10b3a72786 |
14 | 794701755 |
15 | 4632e41c1 |
hex | 2a250b1ff |
11313132031 has 2 divisors, whose sum is σ = 11313132032. Its totient is φ = 11313132030.
The previous prime is 11313131957. The next prime is 11313132053. The reversal of 11313132031 is 13023131311.
It is a strong prime.
It is an emirp because it is prime and its reverse (13023131311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11313132031 - 231 = 9165648383 is a prime.
It is a super-2 number, since 2×113131320312 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311132031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656566015 + 5656566016.
It is an arithmetic number, because the mean of its divisors is an integer number (5656566016).
Almost surely, 211313132031 is an apocalyptic number.
11313132031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313132031 is an equidigital number, since it uses as much as digits as its factorization.
11313132031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 11313132031 its reverse (13023131311), we get a palindrome (24336263342).
The spelling of 11313132031 in words is "eleven billion, three hundred thirteen million, one hundred thirty-two thousand, thirty-one".
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