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11313132301 = 48487233323
BaseRepresentation
bin10101000100101000…
…01011001100001101
31002012102122200000001
422202110023030031
5141132130213201
65110331404301
7550231016002
oct124224131415
932172580001
1011313132301
114885a71819
1222388b3691
1310b3a72933
147947018a9
154632e4301
hex2a250b30d

11313132301 has 4 divisors (see below), whose sum is σ = 11313414112. Its totient is φ = 11312850492.

The previous prime is 11313132251. The next prime is 11313132329. The reversal of 11313132301 is 10323131311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11313132301 - 215 = 11313099533 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313132401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68175 + ... + 165148.

It is an arithmetic number, because the mean of its divisors is an integer number (2828353528).

Almost surely, 211313132301 is an apocalyptic number.

It is an amenable number.

11313132301 is a deficient number, since it is larger than the sum of its proper divisors (281811).

11313132301 is an equidigital number, since it uses as much as digits as its factorization.

11313132301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 281810.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11313132301 its reverse (10323131311), we get a palindrome (21636263612).

The spelling of 11313132301 in words is "eleven billion, three hundred thirteen million, one hundred thirty-two thousand, three hundred one".

Divisors: 1 48487 233323 11313132301