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11313134003442 = 232381979231909
BaseRepresentation
bin1010010010100000101101…
…0101010110010011110010
31111001112011202112012200110
42210220023111112103302
52440323244301102232
640021103152002150
72245230002250135
oct244501325262362
944045152465613
1011313134003442
113671967237407
121328689830356
13640a9331241b
142b17b6b6621c
15149431e39acc
hexa4a0b5564f2

11313134003442 has 16 divisors (see below), whose sum is σ = 23610018790080. Its totient is φ = 3607086203952.

The previous prime is 11313134003441. The next prime is 11313134003467. The reversal of 11313134003442 is 24430043131311.

It is a super-2 number, since 2×113131340034422 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11313134003441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40989615817 + ... + 40989616092.

It is an arithmetic number, because the mean of its divisors is an integer number (1475626174380).

Almost surely, 211313134003442 is an apocalyptic number.

11313134003442 is an abundant number, since it is smaller than the sum of its proper divisors (12296884786638).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313134003442 is a wasteful number, since it uses less digits than its factorization.

11313134003442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81979231937.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 11313134003442 its reverse (24430043131311), we get a palindrome (35743177134753).

The spelling of 11313134003442 in words is "eleven trillion, three hundred thirteen billion, one hundred thirty-four million, three thousand, four hundred forty-two".

Divisors: 1 2 3 6 23 46 69 138 81979231909 163958463818 245937695727 491875391454 1885522333907 3771044667814 5656567001721 11313134003442