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113131342132 = 2228282835533
BaseRepresentation
bin110100101011100100…
…1110100100100110100
3101211000022120122020121
41221113021310210310
53323143110422012
6123545525141324
711113333353544
oct1512711644464
9354008518217
10113131342132
1143a84769876
1219b1355a844
13a88c179a83
145693019324
152e21e82a07
hex1a57274934

113131342132 has 6 divisors (see below), whose sum is σ = 197979848738. Its totient is φ = 56565671064.

The previous prime is 113131342087. The next prime is 113131342133. The reversal of 113131342132 is 231243131311.

113131342132 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 109240826256 + 3890515876 = 330516^2 + 62374^2 .

It is a junction number, because it is equal to n+sod(n) for n = 113131342097 and 113131342106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113131342133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14141417763 + ... + 14141417770.

Almost surely, 2113131342132 is an apocalyptic number.

It is an amenable number.

113131342132 is a deficient number, since it is larger than the sum of its proper divisors (84848506606).

113131342132 is a wasteful number, since it uses less digits than its factorization.

113131342132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28282835537 (or 28282835535 counting only the distinct ones).

The product of its digits is 1296, while the sum is 25.

Adding to 113131342132 its reverse (231243131311), we get a palindrome (344374473443).

The spelling of 113131342132 in words is "one hundred thirteen billion, one hundred thirty-one million, three hundred forty-two thousand, one hundred thirty-two".

Divisors: 1 2 4 28282835533 56565671066 113131342132